Abstract

We first define upper sign continuity for a set-valued mapping and then we consider two types of generalized vector equilibrium problems in topological vector spaces and provide sufficient conditions under which the solution sets are nonempty and compact. Finally, we give an application of our main results. The paper generalizes and improves results obtained by Fang and Huang in (2005).

1. Introduction and Preliminaries

Throughout this paper, unless otherwise specified, we always let and be real Hausdorff topological vector spaces, a nonempty convex set, with pointed closed cone convex values (we recall that a subset of is convex cone and pointed whenever , for and resp.), where denotes all the subsets of Denote by the set of all continuous linear mappings from into For any given let denote the value of at Let and be two mappings. Finally, let be a set-valued mapping. We need the following definitions and results in the sequel.Definition 1.1. Let be a set-valued mapping. One says that is
(i)strongly -pseudomonotone if, for any given and , (ii) -pseudomonotone if, for any given and ,
Remark 1.2. (1) Strongly -pseudomonotonicity implies -pseudomonotonicity.
(2) Let be a set-valued mapping and let be a mapping. If we define for each then strongly -pseudomonotonicity and -pseudomonotonicity reduce to the strongly -pseudomonotonicity and -pseudomonotonicity, of with respect to , respectively, introduced in [1].

Definition 1.3. Let and be two topological spaces. A set-valued mapping is called
(i)upper semicontinuous (u.s.c.) at if for each open set containing , there is an open set containing such that for each is said to be u.s.c. on if it is u.s.c. at all ;(ii)lower semicontinuous (l.s.c.) at if for each open set with , there is an open set containing such that for each is said to be l.s.c. on if it is l.s.c. at all ;(iii)closed if the graph of that is, the set , is a closed set in (iv)compact if the closure of range , that is, , is compact, where
Remark 1.4. One can see that (ii) is equivalent to the following statement:
is l.s.c. at if for each closed set any net converges to and , for all imply that

Lemma 1.5 (see [2]). Let and be two topological spaces. Suppose that is a set-valued mapping. Then the following statements are true.
(a)If is closed and compact, then is u.s.c.(b)Let, for any be compact. If is u.s.c. on then for any net such that and for every there exist and a subnet of such that

For the converse of (b) in Lemma 1.5, we refer the reader to [3].

Definition 1.6. Let be a topological vector space and a topological space. A set-valued mapping is called upper hemicontinuous if the restriction of on straight lines is upper semicontinuous.Definition 1.7. One says that the mapping is -upper sign continuous if, for all the following implication holds: Remark 1.8. Let be a mapping. If we define for all and then Definition 1.7 reduces to the upper sign continuous introduced by Bianchi and Pini in [4]. The upper sign continuity notion was first introduced by Hadjisavvas [5] for a single-valued mapping in the framework of variational inequality problems.

2. Main Results

In this section, we consider the following generalized vector equilibrium problems (for short, GVEPs) in the topological vector space setting:

(GVEP1) find such that and(GVEP2) find such that

Clearly, a solution of GVE is also a solution of problem GVE . We need the following lemma in the sequel.Lemma 2.1. Suppose that
(i) is -pseudomonotone;(ii) for each (iii) is -upper sign continuous;(iv) for each fixed the mapping is convex, that is, Then for any given the following are equivalent:
(I) (II)
Proof. is obvious from the definition of -pseudomonotonicity of Suppose that holds. For each put , where and as above. By (II), we have We claim that Suppose for some Then and so which contradicts (ii) (note the first inclusion follows from (iv), the second inclusion follows from (2.1) and (2.2), and the third follows from the relation Therefore, for all the set is nonempty. Thus, by (iii) there is a Hence, since we get Consequently, This completes the proof.
Remark 2.2. If the set-valued mapping has closed graph and for each fixed the mapping is upper hemicontinuous with nonempty compact values, then condition (iii) in Lemma 2.1 holds. To see this, let and be arbitrary elements of and where By Lemma 1.5(b), there exists a subnet of (without loss of generality ) and such that where Now, since has closed graph (note and as ) and we have Hence, and so This shows that is -upper sign continuous. Therefore, Lemma 2.1 improves Lemma 2.3 in [1].

By a similar argument as in Lemma 2.1 and using Remark 2.2, we can deduce the following result.Lemma 2.3. Suppose that
(i)for each fixed the mapping is upper semicontinuous with compact values;(ii) is strongly -pseudomonotone;(iii) for each (iv) the mapping for each has closed graph;(v) for each fixed the mapping is convex. Then for any given the following are equivalent:
(I) (II)
Remark 2.4. Let be a set-valued mapping. If we define where then Lemma 2.3 reduces to Lemma 3 of Yin and Xu [6].Lemma 2.5. Under the assumptions of Lemma 2.1, the solution set of (GVE ) is convex.Proof. Let and be solutions of (GVE ). By Lemma 2.1, we have From this and condition (iv) of Lemma 2.1, for all we deduce that for all Hence, from Lemma 2.1, we get This means that is a solution of (GVE ). The proof is complete.

Similarly, we can prove the following lemma.Lemma 2.6. Under the assumptions of Lemma 2.3, the solution set of (GVEP1) is convex.Remark 2.7. Lemma 2.5 extends Theorem 3 of Yin and Xu [6] and Lemma 2.5 of Fang and Huang [1].Definition 2.8. Let be a nonempty subset of . A set-valued mapping is said to be a KKM map if for every finite subset of , where denotes the convex hull.Lemma 2.9 ((Fan-KKM lemma) [7]). Let be a nonempty subset of a topological vector space and be a KKM mapping with closed values. Assume that there exists a nonempty compact convex subset of such that is compact. Then Lemma 2.10 (see [8]). Let be a convex subset of a metrizable topological vector space and be a compact upper semicontinuous set-valued mapping with nonempty closed convex values. Then has a fixed point in Theorem 2.11. Let all the assumptions of Lemma 2.1 hold and for each fixed the mapping is lower semicontinuous, where If there exist a nonempty compact subset of and a nonempty convex compact subset of such that, for each there exists such that then the solution set of problem (GVEP2) is nonempty and compact in Proof. Define by We claim that is a KKM mapping. If not, there exist and such that that is, and so, since is a closed convex pointed cone, It follows from condition (iv) of Lemma 2.1 that Now, by combining (2.9) and (2.10), we get which is a contradiction to condition (ii) of Lemma 2.1. Therefore, is a KKM mapping and so is also a KKM mapping (note, for all By Remark 1.4, the values of are closed in (note, for each fixed the mapping is lower semicontinuous) and by our assumption, we obtain that is a closed subset of the compact set and hence is compact in Therefore, fulfils all the assumptions of Lemma 2.9 and so This means that there exists such that Now, it follows from Lemma 2.1 that and hence is a solution of the problem (GVE ). This proves that the solution set of (GVE ) is nonempty. By Lemma 2.1, the solution set of (GVE ) equals and so it is a compact set in (note, in the above that the set is a closed subset of the compact set ). The proof is complete.

As an application of Theorem 2.11, we derive the existence result for a solution of the following problem which consists of finding a such that where and

This problem was considered by Fang and Huang [1] in reflexive Banach spaces setting for a set-valued mapping which is demi- -pseudomonotone.Theorem 2.12. Let be metriziable topological vector space, nonempty convex subset of , , and be two mappings. Assume that
(i)for each fixed the mapping is -pseudomonotone and -upper sign continuous;(ii) for each (iii) for each fixed the mapping is lower semicontinuous;(iv) for each finite dimensional subspace of with , there exist compact subset and compact convex subset of such that , such that Then there exists such that Proof. Let be a finite dimensional subspace with . For each fixed , consider the problem of finding a such that By Theorem 2.11, the problem (2.16) has a nonempty compact solution set in (note, in Theorem 2.11 take ). For , we define a set-valued mapping by Then is a nonempty closed subset of , in fact, is the solution set of (2.16) corresponding to . By Lemma 2.1, we have which is a convex set. By condition (iii) via Remark 1.4, is closed. By (iv), we have . Hence, Lemma 1.5(a) implies that is upper semicontinuous. Hence, satisfies all the assumptions of Lemma 2.1 and so has a fixed point , that is, Set is a finite dimensional subspace with and for By (2.19) and conditions (iii) and (iv), is a nonempty and closed subset of the compact set and hence is compact in . Let be a finite subset of . From the definition of , we have and so has the finite intersection property, so, there is (note, if then where is an arbitrary element of so the family is an open covering for the compact set and so there exist such that which implies that which is a contradiction).
We claim that
Indeed, for each there is such that . Hence, by (note, ) and the definition of , we have and so since was an arbitrary element of then (2.21) is true, for all This completes the proof of claim. From (2.21) and Lemma 2.1, we have and so the proof of the theorem is complete.

Acknowledgments

The authors wish to thank an anonymous referee for useful comments that improved the presentation of the paper. (The first author was in part supported by a Grant from IPM (no. 97490015).)